3t^2-2t-56=0

Solution for 3t^2-2t-56=0 equation:

3t^2-2t-56=0

a = 3; b = -2; c = -56;
Δ = b2-4ac
Δ = -22-4·3·(-56)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-26}{2*3}=\frac{-24}{6}
=-4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+26}{2*3}=\frac{28}{6}
=4+2/3
$